Les Chiens de Guerre

Hi all,

we had different interpretations of the skill "invulnerable", which one is right?
1. The fighter suffers 1 wound per hit, meaning 3x 6s on the combat dice = 3 wounds.
2. The fighter suffers 1 wound per fight, meaning 3x 6s on dice = 1 wound.

Thanks

 :) :) :)

1 HP per hit, always. In combat, 1 hit  mean 1 HP lost, 2 hits 2 HP, and so on. If you catch an invulnerable fighter with an explosion, the same happens: 1 HP per hit regardless of the x/y of the explosion. By the way, you can only hit an invulnerable fighter with 6´s in an explosion.

not exactly :

from any damage source (excluding explosions), the invulnerable fighter suffers only 1 HP per FIGHT (passe d'armes), for any amount of damage at least equal to 1.
if you attack twice in a round and hit, then the invulnerable suffers 2 HP loss.

for explosion damages :
you roll 5 dices as usual, but to do damages, you must obtain 6s on dices to inflict the damages to the invulnerable. Apply damages BUT reduce each hit by 1.

Example : a lemure suffer an explosion (damage values 3/2) : you roll 5 dices and obtain 3,2,4,6,6 : there are 2 hits (on 6s) : then apply damages reduced by 1 per hit (2 damages per hit will become 1 damage per hit).
The lemure will also suffer 2 damages, that will be enough to kill it, I think...  ;)

No, no, he's right.
For close combat, it's 1 dammage by hit (touches)
Look in the definition of invulnerable.

ha, sorry, I've misunderstand on the description. Better read, next time  ;D  :-[

I thought this ability very powerful, then...